A 9 V battery drives a circuit with resistance of 2 Ω. What is the power delivered by the battery?

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Study for the IGCSE Physics Electricity Test. Master key concepts with flashcards and multiple choice questions, each providing hints and explanations. Prepare with confidence for your exam!

Multiple Choice

A 9 V battery drives a circuit with resistance of 2 Ω. What is the power delivered by the battery?

Explanation:
Power delivered by the battery is found using P = VI, and in a resistor circuit the current is I = V/R. With 9 V across 2 Ω, the current is 9/2 = 4.5 A. The power then is P = VI = 9 × 4.5 = 40.5 W. This can also be checked with P = I^2R = (4.5)^2 × 2 = 40.5 W or P = V^2/R = 81/2 = 40.5 W. So the battery delivers 40.5 watts of power.

Power delivered by the battery is found using P = VI, and in a resistor circuit the current is I = V/R. With 9 V across 2 Ω, the current is 9/2 = 4.5 A. The power then is P = VI = 9 × 4.5 = 40.5 W. This can also be checked with P = I^2R = (4.5)^2 × 2 = 40.5 W or P = V^2/R = 81/2 = 40.5 W. So the battery delivers 40.5 watts of power.

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